Factorial of 212
212! = 4733702182912325971198157282773458528972111665671644583063162654840567216299326200333597974632020795344694044141162288574741860330707871653991802372413420954892019572846468089404909755852192508097446724647826768577878987213960691804730882223315446309650598202756704313010742315578131345078364709758529795655446581758477730600169824143256656411069775872000000000000000000000000000000000000000000000000000
403 digits
Sumwise · Maintained by Theo Abbott (pen name) · automated checks · Data: exact arithmetic; unit definitions from NIST SP 811 · Updated · How the checks work
How it is calculated
212! = 212 × 211 × … × 2 × 1 = 4733702182912325971198157282773458528972…
Facts about 212!
| Digits | 403 |
|---|---|
| Trailing zeros | 51 (one for every factor 5 × 2) |
| Stirling estimate | ≈ Infinity |
| 212! ÷ 211! | 212 |
Nearby factorials
| 210! | 105823620292236563784274… (399 digits) |
| 211! | 223287838816619149584818… (401 digits) |
| 213! | 100827856496032543186520… (406 digits) |
| 214! | 215771612901509642419154… (408 digits) |
What are factorials used for?
Counting arrangements: 212! is the number of different orders in which 212 distinct items can be lined up. Factorials also appear in probability, combinations and series.
Counting with 212!
There are 4.7337 × 10^402 different ways to arrange 212 different books on a shelf: 212 choices for the first place, 211 for the second, and so on down to one choice for the last. If you only fill the first three places, as with gold, silver and bronze among 212 runners, there are 212 × 211 × 210 = 9,393,720 possible podiums. If the order does not matter, divide by 3! = 6 to get 1,565,620 ways to choose a group of three. Choosing a pair from 212 people can be done in 22,366 ways.
In probability, if 212 names are drawn out of a hat one at a time, the chance of drawing them in one particular order is 1 in 4.7337 × 10^402. That is why shuffled decks and passwords with many symbols are so hard to guess.
How big is 212!?
212! has 403 digits, so it is larger than the estimated number of atoms in the observable universe (about 10^80). The digits add up to 1593, a multiple of 9, as they are for every factorial from 6! on. Stirling's formula, √(2πn) × (n/e)^n, gives a close estimate without multiplying everything out, and gets more accurate as n grows.
Prime factors of 212!
Every prime up to 212 divides 212!. Legendre's formula counts how often: add ⌊n/p⌋ + ⌊n/p²⌋ + ⌊n/p³⌋ + … for each prime p. For 212! that gives 2^208 × 3^102 × 5^51 × 7^34 × 11^20 × 13^17 × 17^12 × 19^11 × 23^9 × 29^7 × … (47 primes in all). The 51 trailing zeros come from pairing the 51 factors of 5 with factors of 2.
Shuffles where nothing stays put
A related count is the number of derangements of 212 items: orders in which no item ends up in its original place, as in a Secret Santa where nobody draws their own name. The count is the whole number nearest to 212! ÷ e, so about 36.8% of all 4.7337 × 10^402 orders are derangements. From about four items on, that share stays close to 1 ÷ e, roughly 37%, however many items there are.
Computing 212! yourself
In Excel or Google Sheets, type =FACT(212). Spreadsheets keep only 15 significant digits, so from 18! on the result is rounded, and FACT stops at 170!, the largest factorial that fits in a standard floating-point number. In Python, math.factorial(212) returns the exact integer with all 403 digits, because Python integers have no size limit. The gamma function extends factorials to fractions: Γ(n + 1) = n!, so (1/2)! = √π ÷ 2 ≈ 0.8862.
Why is 0! equal to 1?
There is exactly one way to arrange nothing, and the rule n! = n × (n − 1)! only works for n = 1 if 0! = 1. Defining it this way keeps formulas for combinations and series correct at the edges.
How answers are calculated and checked: methodology.
Questions
What is 212 factorial?
212! is the product of every whole number from 1 to 212.
How many digits does 212! have?
403. The number of digits of n! is the whole part of log10(n!) plus one.
How many zeros are at the end of 212!?
51. Count the factors of 5 in the numbers 1 to 212: there are always more factors of 2, so every 5 makes one trailing zero.
Is 212! divisible by 213?
Yes. 213 is not prime, so its factors already appear among the numbers 1 to 212.
What is the last non-zero digit of 212!?
2. Strip the 51 trailing zeros and look at the digit that is left at the end.
What is 213! in terms of 212!?
213! = 213 × 212!. Each factorial is the previous one multiplied by the next whole number.