Sumwise

Factorial of 218

218! = 474026636761029775300387269637885788095262156817399066370617417211711849855339320439555116187613346398029588666682187541512982673977624958479903896285192317905194305948729000291610119288614158064992350939341542922260450295429029866029684735423934482000512012373371714687797391831850026682680610229339536077759026539436134194974261725583681683758619191510313792962560000000000000000000000000000000000000000000000000000

417 digits

Sumwise · Maintained by Theo Abbott (pen name) · automated checks · Data: exact arithmetic; unit definitions from NIST SP 811 · Updated · How the checks work

How it is calculated

218! = 218 × 217 × … × 2 × 1 = 4740266367610297753003872696378857880952…

Facts about 218!

Digits417
Trailing zeros52 (one for every factor 5 × 2)
Stirling estimate≈ Infinity
218! ÷ 217!218

Nearby factorials

216!100204337031461077939455… (413 digits)
217!217443411358270539128618… (415 digits)
219!103811833450665520790784… (420 digits)
220!228386033591464145739726… (422 digits)

What are factorials used for?

Counting arrangements: 218! is the number of different orders in which 218 distinct items can be lined up. Factorials also appear in probability, combinations and series.

Counting with 218!

There are 4.7402 × 10^416 different ways to arrange 218 different books on a shelf: 218 choices for the first place, 217 for the second, and so on down to one choice for the last. If you only fill the first three places, as with gold, silver and bronze among 218 runners, there are 218 × 217 × 216 = 10,218,096 possible podiums. If the order does not matter, divide by 3! = 6 to get 1,703,016 ways to choose a group of three. Choosing a pair from 218 people can be done in 23,653 ways.

In probability, if 218 names are drawn out of a hat one at a time, the chance of drawing them in one particular order is 1 in 4.7402 × 10^416. That is why shuffled decks and passwords with many symbols are so hard to guess.

How big is 218!?

218! has 417 digits, so it is larger than the estimated number of atoms in the observable universe (about 10^80). The digits add up to 1665, a multiple of 9, as they are for every factorial from 6! on. Stirling's formula, √(2πn) × (n/e)^n, gives a close estimate without multiplying everything out, and gets more accurate as n grows.

Prime factors of 218!

Every prime up to 218 divides 218!. Legendre's formula counts how often: add ⌊n/p⌋ + ⌊n/p²⌋ + ⌊n/p³⌋ + … for each prime p. For 218! that gives 2^213 × 3^106 × 5^52 × 7^35 × 11^20 × 13^17 × 17^12 × 19^11 × 23^9 × 29^7 × … (47 primes in all). The 52 trailing zeros come from pairing the 52 factors of 5 with factors of 2.

Shuffles where nothing stays put

A related count is the number of derangements of 218 items: orders in which no item ends up in its original place, as in a Secret Santa where nobody draws their own name. The count is the whole number nearest to 218! ÷ e, so about 36.8% of all 4.7402 × 10^416 orders are derangements. From about four items on, that share stays close to 1 ÷ e, roughly 37%, however many items there are.

Computing 218! yourself

In Excel or Google Sheets, type =FACT(218). Spreadsheets keep only 15 significant digits, so from 18! on the result is rounded, and FACT stops at 170!, the largest factorial that fits in a standard floating-point number. In Python, math.factorial(218) returns the exact integer with all 417 digits, because Python integers have no size limit. The gamma function extends factorials to fractions: Γ(n + 1) = n!, so (1/2)! = √π ÷ 2 ≈ 0.8862.

Why is 0! equal to 1?

There is exactly one way to arrange nothing, and the rule n! = n × (n − 1)! only works for n = 1 if 0! = 1. Defining it this way keeps formulas for combinations and series correct at the edges.

Calculate another factorial

How answers are calculated and checked: methodology.

Questions

What is 218 factorial?

218! is the product of every whole number from 1 to 218.

How many digits does 218! have?

417. The number of digits of n! is the whole part of log10(n!) plus one.

How many zeros are at the end of 218!?

52. Count the factors of 5 in the numbers 1 to 218: there are always more factors of 2, so every 5 makes one trailing zero.

Is 218! divisible by 219?

Yes. 219 is not prime, so its factors already appear among the numbers 1 to 218.

What is the last non-zero digit of 218!?

6. Strip the 52 trailing zeros and look at the digit that is left at the end.

What is 219! in terms of 218!?

219! = 219 × 218!. Each factorial is the previous one multiplied by the next whole number.