Factorial of 253

Counting with 253!

There are 5.1734 × 10^499 different ways to arrange 253 different books on a shelf: 253 choices for the first place, 252 for the second, and so on down to one choice for the last. If you only fill the first three places, as with gold, silver and bronze among 253 runners, there are 253 × 252 × 251 = 16,002,756 possible podiums. If the order does not matter, divide by 3! = 6 to get 2,667,126 ways to choose a group of three. Choosing a pair from 253 people can be done in 31,878 ways.

In probability, if 253 names are drawn out of a hat one at a time, the chance of drawing them in one particular order is 1 in 5.1734 × 10^499. That is why shuffled decks and passwords with many symbols are so hard to guess.

How big is 253!?

253! has 500 digits, so it is larger than the estimated number of atoms in the observable universe (about 10^80). The digits add up to 2025, a multiple of 9, as they are for every factorial from 6! on. Stirling's formula, √(2πn) × (n/e)^n, gives a close estimate without multiplying everything out, and gets more accurate as n grows.

Prime factors of 253!

Every prime up to 253 divides 253!. Legendre's formula counts how often: add ⌊n/p⌋ + ⌊n/p²⌋ + ⌊n/p³⌋ + … for each prime p. For 253! that gives 2^246 × 3^125 × 5^62 × 7^41 × 11^25 × 13^20 × 17^14 × 19^13 × 23^11 × 29^8 × … (54 primes in all). The 62 trailing zeros come from pairing the 62 factors of 5 with factors of 2.

Shuffles where nothing stays put

A related count is the number of derangements of 253 items: orders in which no item ends up in its original place, as in a Secret Santa where nobody draws their own name. The count is the whole number nearest to 253! ÷ e, so about 36.8% of all 5.1734 × 10^499 orders are derangements. From about four items on, that share stays close to 1 ÷ e, roughly 37%, however many items there are.

Computing 253! yourself

In Excel or Google Sheets, type =FACT(253). Spreadsheets keep only 15 significant digits, so from 18! on the result is rounded, and FACT stops at 170!, the largest factorial that fits in a standard floating-point number. In Python, math.factorial(253) returns the exact integer with all 500 digits, because Python integers have no size limit. The gamma function extends factorials to fractions: Γ(n + 1) = n!, so (1/2)! = √π ÷ 2 ≈ 0.8862.

Why is 0! equal to 1?

There is exactly one way to arrange nothing, and the rule n! = n × (n − 1)! only works for n = 1 if 0! = 1. Defining it this way keeps formulas for combinations and series correct at the edges.