Sumwise

Factorial of 265

265! = 4819126545189115249857996730960986251533770366331857368957615661220798628585073783914483646725867739687622506357324016053145562770094251373138342249823796037665437601798081131855895322030484177741468300007032663150819744184955559651767542496475389355118285513974736072922389456001325563316207892398101916582879743108107939148132077795838145760036747741540454073780369029353490610439673321239056214465847859009884948492595992209201420795641312843663252108238808678400000000000000000000000000000000000000000000000000000000000000000

529 digits

Sumwise · Maintained by Theo Abbott (pen name) · automated checks · Data: exact arithmetic; unit definitions from NIST SP 811 · Updated · How the checks work

How it is calculated

265! = 265 × 264 × … × 2 × 1 = 4819126545189115249857996730960986251533…

Facts about 265!

Digits529
Trailing zeros65 (one for every factor 5 × 2)
Stirling estimate≈ Infinity
265! ÷ 264!265

Nearby factorials

263!688840272325488171792166… (524 digits)
264!181853831893928877353131… (527 digits)
266!128188766102030465646222… (532 digits)
267!342264005492421343275414… (534 digits)

What are factorials used for?

Counting arrangements: 265! is the number of different orders in which 265 distinct items can be lined up. Factorials also appear in probability, combinations and series.

Counting with 265!

There are 4.8191 × 10^528 different ways to arrange 265 different books on a shelf: 265 choices for the first place, 264 for the second, and so on down to one choice for the last. If you only fill the first three places, as with gold, silver and bronze among 265 runners, there are 265 × 264 × 263 = 18,399,480 possible podiums. If the order does not matter, divide by 3! = 6 to get 3,066,580 ways to choose a group of three. Choosing a pair from 265 people can be done in 34,980 ways.

In probability, if 265 names are drawn out of a hat one at a time, the chance of drawing them in one particular order is 1 in 4.8191 × 10^528. That is why shuffled decks and passwords with many symbols are so hard to guess.

How big is 265!?

265! has 529 digits, so it is larger than the estimated number of atoms in the observable universe (about 10^80). The digits add up to 2106, a multiple of 9, as they are for every factorial from 6! on. Stirling's formula, √(2πn) × (n/e)^n, gives a close estimate without multiplying everything out, and gets more accurate as n grows.

Prime factors of 265!

Every prime up to 265 divides 265!. Legendre's formula counts how often: add ⌊n/p⌋ + ⌊n/p²⌋ + ⌊n/p³⌋ + … for each prime p. For 265! that gives 2^262 × 3^130 × 5^65 × 7^42 × 11^26 × 13^21 × 17^15 × 19^13 × 23^11 × 29^9 × … (56 primes in all). The 65 trailing zeros come from pairing the 65 factors of 5 with factors of 2.

Shuffles where nothing stays put

A related count is the number of derangements of 265 items: orders in which no item ends up in its original place, as in a Secret Santa where nobody draws their own name. The count is the whole number nearest to 265! ÷ e, so about 36.8% of all 4.8191 × 10^528 orders are derangements. From about four items on, that share stays close to 1 ÷ e, roughly 37%, however many items there are.

Computing 265! yourself

In Excel or Google Sheets, type =FACT(265). Spreadsheets keep only 15 significant digits, so from 18! on the result is rounded, and FACT stops at 170!, the largest factorial that fits in a standard floating-point number. In Python, math.factorial(265) returns the exact integer with all 529 digits, because Python integers have no size limit. The gamma function extends factorials to fractions: Γ(n + 1) = n!, so (1/2)! = √π ÷ 2 ≈ 0.8862.

Why is 0! equal to 1?

There is exactly one way to arrange nothing, and the rule n! = n × (n − 1)! only works for n = 1 if 0! = 1. Defining it this way keeps formulas for combinations and series correct at the edges.

Calculate another factorial

How answers are calculated and checked: methodology.

Questions

What is 265 factorial?

265! is the product of every whole number from 1 to 265.

How many digits does 265! have?

529. The number of digits of n! is the whole part of log10(n!) plus one.

How many zeros are at the end of 265!?

65. Count the factors of 5 in the numbers 1 to 265: there are always more factors of 2, so every 5 makes one trailing zero.

Is 265! divisible by 266?

Yes. 266 is not prime, so its factors already appear among the numbers 1 to 265.

What is the last non-zero digit of 265!?

4. Strip the 65 trailing zeros and look at the digit that is left at the end.

What is 266! in terms of 265!?

266! = 266 × 265!. Each factorial is the previous one multiplied by the next whole number.