Sumwise

Factorial of 290

290! = 60316116183878209766117976235613285674586630483425933084029202472047670485819885245164731849642810548475941525840095286214179522721593990128930118982329294365767928511440729849320802184711774330495375545958604447485894133813040753046757845833254416671760299033093062086252031499964109155039154660288221882477747977319966161835146771580496981591719779344293705580123767115637822100135690925946157620356054977604029114048086866036189530542932814283520706747909108718372525130923228359166396038270919098494331151103662489600000000000000000000000000000000000000000000000000000000000000000000000

590 digits

Sumwise · Maintained by Theo Abbott (pen name) · automated checks · Data: exact arithmetic; unit definitions from NIST SP 811 · Updated · How the checks work

How it is calculated

290! = 290 × 289 × … × 2 × 1 = 6031611618387820976611797623561328567458…

Facts about 290!

Digits590
Trailing zeros71 (one for every factor 5 × 2)
Stirling estimate≈ Infinity
290! ÷ 289!290

Nearby factorials

288!719676842666486216037680… (585 digits)
289!207986607530614516434889… (588 digits)
291!175519898095085590419403… (593 digits)
292!512518102437649924024657… (595 digits)

What are factorials used for?

Counting arrangements: 290! is the number of different orders in which 290 distinct items can be lined up. Factorials also appear in probability, combinations and series.

Counting with 290!

There are 6.0316 × 10^589 different ways to arrange 290 different books on a shelf: 290 choices for the first place, 289 for the second, and so on down to one choice for the last. If you only fill the first three places, as with gold, silver and bronze among 290 runners, there are 290 × 289 × 288 = 24,137,280 possible podiums. If the order does not matter, divide by 3! = 6 to get 4,022,880 ways to choose a group of three. Choosing a pair from 290 people can be done in 41,905 ways.

In probability, if 290 names are drawn out of a hat one at a time, the chance of drawing them in one particular order is 1 in 6.0316 × 10^589. That is why shuffled decks and passwords with many symbols are so hard to guess.

How big is 290!?

290! has 590 digits, so it is larger than the estimated number of atoms in the observable universe (about 10^80). The digits add up to 2313, a multiple of 9, as they are for every factorial from 6! on. Stirling's formula, √(2πn) × (n/e)^n, gives a close estimate without multiplying everything out, and gets more accurate as n grows.

Prime factors of 290!

Every prime up to 290 divides 290!. Legendre's formula counts how often: add ⌊n/p⌋ + ⌊n/p²⌋ + ⌊n/p³⌋ + … for each prime p. For 290! that gives 2^287 × 3^142 × 5^71 × 7^46 × 11^28 × 13^23 × 17^18 × 19^15 × 23^12 × 29^10 × … (61 primes in all). The 71 trailing zeros come from pairing the 71 factors of 5 with factors of 2.

Shuffles where nothing stays put

A related count is the number of derangements of 290 items: orders in which no item ends up in its original place, as in a Secret Santa where nobody draws their own name. The count is the whole number nearest to 290! ÷ e, so about 36.8% of all 6.0316 × 10^589 orders are derangements. From about four items on, that share stays close to 1 ÷ e, roughly 37%, however many items there are.

Computing 290! yourself

In Excel or Google Sheets, type =FACT(290). Spreadsheets keep only 15 significant digits, so from 18! on the result is rounded, and FACT stops at 170!, the largest factorial that fits in a standard floating-point number. In Python, math.factorial(290) returns the exact integer with all 590 digits, because Python integers have no size limit. The gamma function extends factorials to fractions: Γ(n + 1) = n!, so (1/2)! = √π ÷ 2 ≈ 0.8862.

Why is 0! equal to 1?

There is exactly one way to arrange nothing, and the rule n! = n × (n − 1)! only works for n = 1 if 0! = 1. Defining it this way keeps formulas for combinations and series correct at the edges.

Calculate another factorial

How answers are calculated and checked: methodology.

Questions

What is 290 factorial?

290! is the product of every whole number from 1 to 290.

How many digits does 290! have?

590. The number of digits of n! is the whole part of log10(n!) plus one.

How many zeros are at the end of 290!?

71. Count the factors of 5 in the numbers 1 to 290: there are always more factors of 2, so every 5 makes one trailing zero.

Is 290! divisible by 291?

Yes. 291 is not prime, so its factors already appear among the numbers 1 to 290.

What is the last non-zero digit of 290!?

6. Strip the 71 trailing zeros and look at the digit that is left at the end.

What is 291! in terms of 290!?

291! = 291 × 290!. Each factorial is the previous one multiplied by the next whole number.