Sumwise

Factorial of 490

490! = 1367870284785684026772991737862074903437625025383139101736084469713406918047247594105704790815029148293989927805372618469298049868646843230957336939045242869008924375139517649232016542816216144732547633464928001778392713416439653309888785183453664980521144689776742417355175704316163383082083288541709004323103078843487949010791704803907018015854085492663078732816059394656804688284023548118207393737821483700506216514350357431814676111048385145550173425219601276002508402991422273874007370313463139231520951050878639743324597284796160322440257070177616152988436774944788612558270300447280359608840656684282068229918732911552660210415991332700451640972922059394550912107067645081477317530646908008380371724847691286701216630375200807002807100567204186971905996512689001405496613789578233889914311589027516052374533799150103069745275134400857802104504999117851807653325870632724834955780779673311573823268040183377128133354800417142884216564788947290881899909214192915449276342004449542144000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

1108 digits

Sumwise · Maintained by Theo Abbott (pen name) · automated checks · Data: exact arithmetic; unit definitions from NIST SP 811 · Updated · How the checks work

How it is calculated

490! = 490 × 489 × … × 2 × 1 = 1367870284785684026772991737862074903437…

Facts about 490!

Digits1108
Trailing zeros120 (one for every factor 5 × 2)
Stirling estimate≈ Infinity
490! ÷ 489!490

Nearby factorials

488!570873621629182432608401… (1102 digits)
489!279157200976670209545508… (1105 digits)
491!671624309829770857145538… (1110 digits)
492!330439160436247261715605… (1113 digits)

What are factorials used for?

Counting arrangements: 490! is the number of different orders in which 490 distinct items can be lined up. Factorials also appear in probability, combinations and series.

Counting with 490!

There are 1.3678 × 10^1107 different ways to arrange 490 different books on a shelf: 490 choices for the first place, 489 for the second, and so on down to one choice for the last. If you only fill the first three places, as with gold, silver and bronze among 490 runners, there are 490 × 489 × 488 = 116,929,680 possible podiums. If the order does not matter, divide by 3! = 6 to get 19,488,280 ways to choose a group of three. Choosing a pair from 490 people can be done in 119,805 ways.

In probability, if 490 names are drawn out of a hat one at a time, the chance of drawing them in one particular order is 1 in 1.3678 × 10^1107. That is why shuffled decks and passwords with many symbols are so hard to guess.

How big is 490!?

490! has 1108 digits, so it is larger than the estimated number of atoms in the observable universe (about 10^80). The digits add up to 4284, a multiple of 9, as they are for every factorial from 6! on. Stirling's formula, √(2πn) × (n/e)^n, gives a close estimate without multiplying everything out, and gets more accurate as n grows.

Prime factors of 490!

Every prime up to 490 divides 490!. Legendre's formula counts how often: add ⌊n/p⌋ + ⌊n/p²⌋ + ⌊n/p³⌋ + … for each prime p. For 490! that gives 2^484 × 3^243 × 5^120 × 7^81 × 11^48 × 13^39 × 17^29 × 19^26 × 23^21 × 29^16 × … (93 primes in all). The 120 trailing zeros come from pairing the 120 factors of 5 with factors of 2.

Shuffles where nothing stays put

A related count is the number of derangements of 490 items: orders in which no item ends up in its original place, as in a Secret Santa where nobody draws their own name. The count is the whole number nearest to 490! ÷ e, so about 36.8% of all 1.3678 × 10^1107 orders are derangements. From about four items on, that share stays close to 1 ÷ e, roughly 37%, however many items there are.

Computing 490! yourself

In Excel or Google Sheets, type =FACT(490). Spreadsheets keep only 15 significant digits, so from 18! on the result is rounded, and FACT stops at 170!, the largest factorial that fits in a standard floating-point number. In Python, math.factorial(490) returns the exact integer with all 1108 digits, because Python integers have no size limit. The gamma function extends factorials to fractions: Γ(n + 1) = n!, so (1/2)! = √π ÷ 2 ≈ 0.8862.

Why is 0! equal to 1?

There is exactly one way to arrange nothing, and the rule n! = n × (n − 1)! only works for n = 1 if 0! = 1. Defining it this way keeps formulas for combinations and series correct at the edges.

Calculate another factorial

How answers are calculated and checked: methodology.

Questions

What is 490 factorial?

490! is the product of every whole number from 1 to 490.

How many digits does 490! have?

1108. The number of digits of n! is the whole part of log10(n!) plus one.

How many zeros are at the end of 490!?

120. Count the factors of 5 in the numbers 1 to 490: there are always more factors of 2, so every 5 makes one trailing zero.

Is 490! divisible by 491?

No. 491 is prime and bigger than every factor of 490!, so it cannot divide it (Wilson's theorem says 490! leaves a remainder of 490 when divided by 491).

What is the last non-zero digit of 490!?

4. Strip the 120 trailing zeros and look at the digit that is left at the end.

What is 491! in terms of 490!?

491! = 491 × 490!. Each factorial is the previous one multiplied by the next whole number.