Factorial of 260
260! = 3830195860836169235117497985604491875279556752309096960191300817480651475135399533485285838275429773913773383359294010103333339344249624060099745511339849626153802980398232848965472622820196848860832049579523313702327662760125732592551956622024712475139889122106940319324041688318583612166708334763727216738353107304842707002261430265483385206376839110078156900663427220806900528365808580136352143713956803295894115605151395493267411709188354023557693440000000000000000000000000000000000000000000000000000000000000000
517 digits
Sumwise · Maintained by Theo Abbott (pen name) · automated checks · Data: exact arithmetic; unit definitions from NIST SP 811 · Updated · How the checks work
How it is calculated
260! = 260 × 259 × … × 2 × 1 = 3830195860836169235117497985604491875279…
Facts about 260!
| Digits | 517 |
|---|---|
| Trailing zeros | 64 (one for every factor 5 × 2) |
| Stirling estimate | ≈ Infinity |
| 260! ÷ 259! | 260 |
Nearby factorials
| 258! | 568784654118825250240198… (512 digits) |
| 259! | 147315225416775739812211… (515 digits) |
| 261! | 999681119678240170365666… (519 digits) |
| 262! | 261916453355698924635804… (522 digits) |
What are factorials used for?
Counting arrangements: 260! is the number of different orders in which 260 distinct items can be lined up. Factorials also appear in probability, combinations and series.
Counting with 260!
There are 3.8301 × 10^516 different ways to arrange 260 different books on a shelf: 260 choices for the first place, 259 for the second, and so on down to one choice for the last. If you only fill the first three places, as with gold, silver and bronze among 260 runners, there are 260 × 259 × 258 = 17,373,720 possible podiums. If the order does not matter, divide by 3! = 6 to get 2,895,620 ways to choose a group of three. Choosing a pair from 260 people can be done in 33,670 ways.
In probability, if 260 names are drawn out of a hat one at a time, the chance of drawing them in one particular order is 1 in 3.8301 × 10^516. That is why shuffled decks and passwords with many symbols are so hard to guess.
How big is 260!?
260! has 517 digits, so it is larger than the estimated number of atoms in the observable universe (about 10^80). The digits add up to 1962, a multiple of 9, as they are for every factorial from 6! on. Stirling's formula, √(2πn) × (n/e)^n, gives a close estimate without multiplying everything out, and gets more accurate as n grows.
Prime factors of 260!
Every prime up to 260 divides 260!. Legendre's formula counts how often: add ⌊n/p⌋ + ⌊n/p²⌋ + ⌊n/p³⌋ + … for each prime p. For 260! that gives 2^258 × 3^127 × 5^64 × 7^42 × 11^25 × 13^21 × 17^15 × 19^13 × 23^11 × 29^8 × … (55 primes in all). The 64 trailing zeros come from pairing the 64 factors of 5 with factors of 2.
Shuffles where nothing stays put
A related count is the number of derangements of 260 items: orders in which no item ends up in its original place, as in a Secret Santa where nobody draws their own name. The count is the whole number nearest to 260! ÷ e, so about 36.8% of all 3.8301 × 10^516 orders are derangements. From about four items on, that share stays close to 1 ÷ e, roughly 37%, however many items there are.
Computing 260! yourself
In Excel or Google Sheets, type =FACT(260). Spreadsheets keep only 15 significant digits, so from 18! on the result is rounded, and FACT stops at 170!, the largest factorial that fits in a standard floating-point number. In Python, math.factorial(260) returns the exact integer with all 517 digits, because Python integers have no size limit. The gamma function extends factorials to fractions: Γ(n + 1) = n!, so (1/2)! = √π ÷ 2 ≈ 0.8862.
Why is 0! equal to 1?
There is exactly one way to arrange nothing, and the rule n! = n × (n − 1)! only works for n = 1 if 0! = 1. Defining it this way keeps formulas for combinations and series correct at the edges.
How answers are calculated and checked: methodology.
Questions
What is 260 factorial?
260! is the product of every whole number from 1 to 260.
How many digits does 260! have?
517. The number of digits of n! is the whole part of log10(n!) plus one.
How many zeros are at the end of 260!?
64. Count the factors of 5 in the numbers 1 to 260: there are always more factors of 2, so every 5 makes one trailing zero.
Is 260! divisible by 261?
Yes. 261 is not prime, so its factors already appear among the numbers 1 to 260.
What is the last non-zero digit of 260!?
4. Strip the 64 trailing zeros and look at the digit that is left at the end.
What is 261! in terms of 260!?
261! = 261 × 260!. Each factorial is the previous one multiplied by the next whole number.